what happens to the centripetal force if mass is doubled

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Troy spins a brawl attached to a string around in a vertical circle. Assume the ball travels at constant speed during its circular path. Which of the following is not constant throughout the ball'southward path?

Possible Answers:

The rate at which the string does piece of work on the brawl

Force of gravity on the brawl

Angular momentum of the ball

All of these are abiding

Tension in the string

Correct answer:

Tension in the cord

Caption:

Let's go through each answer choice one by 1. The strength of gravity on the ball is always its mass times gravity, which is constant. The string's pull on the brawl is always perpendicular to the ball's move, so it isn't doing any work, and thus has a abiding rate of work $(0\frac{J}{s})$ . The ball'due south angular momentum is ever constant since its mass, the radius of the circle it's traveling in, and its speed are constant. The only the changing is the tensionin the string. This is true because the ball needs the same heart pulling forcefulness (centripetal force) throughout its path, but this centripetal force is constantly changing direction. For example, at the top of its path, the centripetal force must be down considering that's the management of the center of its circumvolve of motion, but at the bottom, the centripetal force must be upwardly. There are two forces on the ball, gravity and tension. The force of gravity is always downward and abiding, then the tension needs to change in social club to keep the center pulling force the same. For example, when the ball is at the lesser of the circle, the strength of gravity is away from the center of the circumvolve, and so tension must be higher to keep the center pull constant.

An airplane is traveling at $100\frac{m}{s}$ and performs a vertical loop in. Determine the cyberspace forcefulness on the 50kg pilot at the bottom of the loop.

Correct respond:

6300N

Caption:

Circumference of a circumvolve:

$2\pi r=C$

Distance plane travels during loop (which will be the circumference)

v*t=d

$100\frac{m}{s}*5s=500m$

$2\pi r=500$

r=79.5meters

Centripetal acceleration:

$\frac{v^2}{r}=a_{centripetal}$

Plugging in values:

$\frac{100^2}{79.5}=a_{centripetal}$

$a_{centripetal}=126\frac{m}{s^2}$

F=ma

F=50*126

F=6300N

An airplane is traveling at $100\frac{m}{s}$ and performs a vertical loop in. Determine the force due to the seat on the 50kg pilot at the bottom of the loop

Correct answer:

6790N

Caption:

Circumference of a circumvolve:

$2\pi r=C$

Distance plane travels during loop (which will be the circumference)

v*t=d

$100\frac{m}{s}*5s=500m$

$2\pi r=500$

r=79.5meters

Centripetal acceleration:

$\frac{v^2}{r}=a_{centripetal}$

Plugging in values:

$\frac{100^2}{79.5}=a_{centripetal}$

$a_{centripetal}=126\frac{m}{s^2}$

F=ma

F=50*126

F=6300N

$F_{net}=F_{seat}+F_{gravity}$

$6300=F_{seat}-9.8*50$

$6790N=F_{seat}$

An aeroplane is traveling at $100\frac{m}{s}$ and performs a vertical loop in. Determine the radius of the loop.

Correct answer:

79.5m

Explanation:

Circumference of a circle:

$2\pi r=C$

Altitude airplane travels during loop (which volition be the circumference)

v*t=d

$100\frac{m}{s}*5s=500m$

$2\pi r=500$

r=79.5m

A 4kg model train completes a circle of radius in 7 s . Make up one's mind the centripetal acceleration.

Right answer:

$.805\frac{m}{s^2}$

Explanation:

1 circle is equal to $2\pi\ rad$ , thus the linear velocity is:

$\frac{1 circle}{7 s}*\frac{2\pi\ rad}{1 circle}*\frac{1m}{rad}=\frac{.897m}{s}$

Using

$a_{centripital}=\frac{v^2}{r}$

$a_{centripital}=\frac{.897^2}{1}$

$a_{centripital}=.805\frac{m}{s^2}$

A 4kg model train completes a circumvolve of radius in 7 s . Determine the centripetal force.

Correct answer:

3.22N

Explanation:

1 circle is equal to $2\pi\ rad$ , thus the linear velocity is

$\frac{1 circle}{7 s}*\frac{2\pi\ rad}{1 circle}*\frac{1m}{rad}=\frac{.897m}{s}$

Using

$a_{centripital}=\frac{v^2}{r}$

$a_{centripital}=\frac{.897^2}{1}$

$a_{centripital}=.805\frac{m}{s^2}$

Use Newton's second law:

F=ma

F=4*.805

F=3.22N

A 4kg model train completes a circle of radius in 7 s . Determine the angular momentum.

Correct answer:

$3.588kg\frac{m^2}{s}$

Explanation:

One circle is equal to $2\pi\ rad$ , thus the linear velocity is:

$\frac{1 circle}{7 s}*\frac{2\pi\ rad}{1 circle}*\frac{1m}{rad}=\frac{.897m}{s}$

The definition of angular momentum:

L=mvr

Plugging in values:

L=4*.897*1

$L=3.588kg\frac{m^2}{s}$

An object has a mass Thousand, velocity V, and moves in a circle with radius R.

What happens to the centripetal acceleration on the object when the mass is doubled?

Possible Answers:

The centripetal acceleration remains the same.

The centripetal acceleration is halved.

The centripetal dispatch remains the aforementioned.

The centripetal acceleration is doubled.

The centripetal acceleration is quadrupled.

Correct answer:

The centripetal dispatch remains the same.

Explanation:

The equation for centripetal acceleration is:

$a_c=\frac{v^2}{r}$

Where a_c is the centripetal acceleration on an object, is the velocity of an object, and is the radius in which the object moves in a circumvolve.

We tin meet that mass does non play a role in the centripetal acceleration of an object, then no affair what happens to the mass, the centripetal acceleration remains the same.

An object has a mass M, velocity 5, and moves in a circumvolve with radius R.

What happens to the centripetal acceleration on the object when the radius is halved?

Possible Answers:

The centripetal acceleration of the object goes to zip.

The centripetal acceleration of the object is halved.

The centripetal acceleration of the object is quadrupled.

The centripetal acceleration of the object remains the aforementioned.

The centripetal acceleration of the object is doubled.

Correct reply:

The centripetal acceleration of the object is doubled.

Caption:

The equation for centripetal acceleration is:

$a_c=\frac{v^2}{r}$

Where a_c is the centripetal dispatch on an object, is the velocity of an object, and is the radius in which the object moves in a circumvolve.

The radius has an inverse relationship with centripetal acceleration, so when the radius is halved, the centripetal dispatch is doubled.

An object has a mass M, velocity Five, and moves in a circle with radius R.

What happens to the centripetal acceleration on the object when the velocity is doubled?

Possible Answers:

The centripetal acceleration of the object is quadrupled.

The centripetal dispatch of the object is doubled.

The centripetal acceleration of the object is halved.

The centripetal dispatch of the object remains the same.

The centripetal acceleration of the object goes to zero.

Correct respond:

The centripetal acceleration of the object is quadrupled.

Explanation:

The equation for centripetal acceleration is:

$a_c=\frac{v^2}{r}$

Where a_c is the centripetal acceleration on an object, is the velocity of an object, and is the radius in which the object moves in a circle.

The velocity has an quadratic relationship with centripetal dispatch, and then when the velocity is doubled, the centripetal acceleration is quadrupled.

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what happens to the centripetal force if mass is doubled

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